![University: Calculus 1] How to evaluate this limit using the L'Hôpital's rule to get e^9? We have not covered the limit chain rule in class. : r/HomeworkHelp University: Calculus 1] How to evaluate this limit using the L'Hôpital's rule to get e^9? We have not covered the limit chain rule in class. : r/HomeworkHelp](https://preview.redd.it/university-calculus-1-how-to-evaluate-this-limit-using-the-v0-b7zrwwnfts2a1.jpg?width=640&crop=smart&auto=webp&s=01bcabce243e2d6f93b50a4e7a1a0025b981f325)
University: Calculus 1] How to evaluate this limit using the L'Hôpital's rule to get e^9? We have not covered the limit chain rule in class. : r/HomeworkHelp
![University: Calculus 1] How is the limit chain rule used in this scenario? It should be e^9. : r/HomeworkHelp University: Calculus 1] How is the limit chain rule used in this scenario? It should be e^9. : r/HomeworkHelp](https://preview.redd.it/university-calculus-1-how-is-the-limit-chain-rule-used-in-v0-0pt67gnehd2a1.jpg?width=640&crop=smart&auto=webp&s=3f24d5ea95540d796d6fa7343113d6575d04af2d)
University: Calculus 1] How is the limit chain rule used in this scenario? It should be e^9. : r/HomeworkHelp
![SOLVED: Graph > Examples % Solution lim(x->0) (3x - 5x) = 5 Steps Junx- ((3x+5x) Apply exponent rule: a = e^(at) = e^(r-ln(a)) * Q (3x - 5x) = e^(ln(3x) - (edl(3x+5x) SOLVED: Graph > Examples % Solution lim(x->0) (3x - 5x) = 5 Steps Junx- ((3x+5x) Apply exponent rule: a = e^(at) = e^(r-ln(a)) * Q (3x - 5x) = e^(ln(3x) - (edl(3x+5x)](https://cdn.numerade.com/ask_images/862e5f4fcacf4343a9c7ea1b7114fbe6.jpg)
SOLVED: Graph > Examples % Solution lim(x->0) (3x - 5x) = 5 Steps Junx- ((3x+5x) Apply exponent rule: a = e^(at) = e^(r-ln(a)) * Q (3x - 5x) = e^(ln(3x) - (edl(3x+5x)
![calculus - Chain rule proof is a bit unclear. What is epsilion in this proof? - Mathematics Stack Exchange calculus - Chain rule proof is a bit unclear. What is epsilion in this proof? - Mathematics Stack Exchange](https://i.stack.imgur.com/BTEI3.png)